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Old 06-29-2012, 01:39 PM   #1
28Bunkhouse
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Question Wind force exerted on side of TT?

Does any one out there know how much force per square foot is exerted on the side of a TT at different wind speeds? Is there some kind of chart?
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Old 06-29-2012, 05:15 PM   #2
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It's called the "White Knuckle Sway Chart" ... When you can't feel your finger tips anymore it's time to pull into a rest area. Really, there are too many variables ( trailer shape, wind direction, other vehicles, etc. ) to make any kind of chart. Experience is the best teacher ..... if you are not comfortable, it's too windy. Slow down and travel safely, Hank
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Old 06-29-2012, 07:05 PM   #3
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I don't know how much it takes, but I can tell you that the 85 mph winds we had here in Ohio tonight were enough to move my 291 sideways about 3". That was with an X chock on both sides and all 4 stabilizers down. And the back of the trailer was facing west. Standby gen is running right now, hear it might be a couple of days before we have power.
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Old 06-29-2012, 08:18 PM   #4
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Originally Posted by Laredo291OH View Post
I don't know how much it takes, but I can tell you that the 85 mph winds we had here in Ohio tonight were enough to move my 291 sideways about 3". That was with an X chock on both sides and all 4 stabilizers down. And the back of the trailer was facing west. Standby gen is running right now, hear it might be a couple of days before we have power.
Damn........
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Old 06-30-2012, 07:00 AM   #5
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Laredo291OH, Howdy;

Where in Ohio are ya ???

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Old 06-30-2012, 07:11 AM   #6
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Originally Posted by 28Bunkhouse View Post
Does any one out there know how much force per square foot is exerted on the side of a TT at different wind speeds? Is there some kind of chart?
The Generic Formula

For using the actual sustained wind speed expected (were we to actually determine it) :

Force, F = A x P x Cd

A = The projected area of the item

P , Wind pressure (Psf), = .00256 x V^2 (V= wind speed in Mph)

Cd , Drag coefficient, = 2.0 for flat plates. For a long cylinder (like most antenna tubes), Cd = 1.2.
Note the relationship between them is 1.2/2 = .6, not quite 2/3.

This is the force on a discreet constant section. I.E. A length of tubing or some other such member that is part of a structure. The Force per unit area would be found by setting the area to 1.
This is the simplest form of all that stuff in the textbooks, at standard temp and atmospheric pressure, for the range of wind speeds we see and the general size of the members on our toys.

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Old 06-30-2012, 07:23 AM   #7
hankaye
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Cool Canuck, Howdy;

When you wrote this you stated;

"P , Wind pressure (Psf), = .00256 x V^2 (V= wind speed in Mph)"

What does the ^ symbol stand for us non mathmatical types ???

Thanks for posting the formula.

hankaye
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Old 06-30-2012, 09:28 AM   #8
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V^2 means v squared
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Old 06-30-2012, 11:27 AM   #9
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christopherglenn, Howdy;

Thanks. I was think so, just need it verified...

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Old 07-06-2012, 09:27 AM   #10
28Bunkhouse
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Wind calculation

Thanks guys, I take it I would use 2 for a drag coefficient for the side of the trailer?
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